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14053042555 = 5163149911503
BaseRepresentation
bin11010001011010000…
…00110100101111011
31100021101021112021121
431011220012211323
5212240034330210
610242245250111
71005150614356
oct150550064573
940241245247
1014053042555
115a61637962
122882403937
13142c5c10c6
1497456329d
15573b0e6da
hex345a0697b

14053042555 has 16 divisors (see below), whose sum is σ = 16979904000. Its totient is φ = 11165037408.

The previous prime is 14053042529. The next prime is 14053042583. The reversal of 14053042555 is 55524035041.

14053042555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 14053042555 - 215 = 14053009787 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14053042555.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1215934 + ... + 1227436.

It is an arithmetic number, because the mean of its divisors is an integer number (1061244000).

Almost surely, 214053042555 is an apocalyptic number.

14053042555 is a deficient number, since it is larger than the sum of its proper divisors (2926861445).

14053042555 is a wasteful number, since it uses less digits than its factorization.

14053042555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13170.

The product of its (nonzero) digits is 60000, while the sum is 34.

Adding to 14053042555 its reverse (55524035041), we get a palindrome (69577077596).

The spelling of 14053042555 in words is "fourteen billion, fifty-three million, forty-two thousand, five hundred fifty-five".

Divisors: 1 5 163 815 1499 7495 11503 57515 244337 1221685 1874989 9374945 17242997 86214985 2810608511 14053042555