Base | Representation |
---|---|
bin | 11010001011010000… |
… | …01000100000100011 |
3 | 1100021101021221001021 |
4 | 31011220020200203 |
5 | 212240040103103 |
6 | 10242245350311 |
7 | 1005150646300 |
oct | 150550104043 |
9 | 40241257037 |
10 | 14053050403 |
11 | 5a61642847 |
12 | 2882408397 |
13 | 142c5c4852 |
14 | 9745660a7 |
15 | 573b11bbd |
hex | 345a08823 |
14053050403 has 12 divisors (see below), whose sum is σ = 16372497600. Its totient is φ = 12026998032.
The previous prime is 14053050383. The next prime is 14053050433. The reversal of 14053050403 is 30405035041.
It is not a de Polignac number, because 14053050403 - 25 = 14053050371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14053050433) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 187603 + ... + 251596.
It is an arithmetic number, because the mean of its divisors is an integer number (1364374800).
Almost surely, 214053050403 is an apocalyptic number.
14053050403 is a deficient number, since it is larger than the sum of its proper divisors (2319447197).
14053050403 is an equidigital number, since it uses as much as digits as its factorization.
14053050403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 439866 (or 439859 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 25.
Adding to 14053050403 its reverse (30405035041), we get a palindrome (44458085444).
The spelling of 14053050403 in words is "fourteen billion, fifty-three million, fifty thousand, four hundred three".
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