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14053103141053 = 106313220228731
BaseRepresentation
bin1100110001111111111000…
…1110001000000010111101
31211202110111220212000122111
43030133332032020002331
53320221223401003203
645515523443414021
72650205665532554
oct314377616100275
954673456760574
1014053103141053
1145289843a5519
1216ab703984311
137ac28187b5c2
14368260d72d9b
15195847e0c26d
hexcc7fe3880bd

14053103141053 has 4 divisors (see below), whose sum is σ = 14066323370848. Its totient is φ = 14039882911260.

The previous prime is 14053103141023. The next prime is 14053103141081. The reversal of 14053103141053 is 35014130135041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14053103141053 - 233 = 14044513206461 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14053103141023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6610113303 + ... + 6610115428.

It is an arithmetic number, because the mean of its divisors is an integer number (3516580842712).

Almost surely, 214053103141053 is an apocalyptic number.

It is an amenable number.

14053103141053 is a deficient number, since it is larger than the sum of its proper divisors (13220229795).

14053103141053 is a wasteful number, since it uses less digits than its factorization.

14053103141053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13220229794.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 14053103141053 its reverse (35014130135041), we get a palindrome (49067233276094).

The spelling of 14053103141053 in words is "fourteen trillion, fifty-three billion, one hundred three million, one hundred forty-one thousand, fifty-three".

Divisors: 1 1063 13220228731 14053103141053