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14053125114055 = 516931660144727
BaseRepresentation
bin1100110001111111111110…
…0001111100100011000111
31211202110120110012100221101
43030133333201330203013
53320221300012122210
645515525550400531
72650206353360026
oct314377741744307
954673513170841
1014053125114055
114528995843125
1216ab70b200147
137ac2862a2a91
14368263c528bd
15195849ceca3a
hexcc7ff87c8c7

14053125114055 has 8 divisors (see below), whose sum is σ = 16873711015392. Its totient is φ = 11235859505568.

The previous prime is 14053125114037. The next prime is 14053125114059. The reversal of 14053125114055 is 55041152135041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14053125114055 - 223 = 14053116725447 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14053125114059) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 830063899 + ... + 830080828.

It is an arithmetic number, because the mean of its divisors is an integer number (2109213876924).

Almost surely, 214053125114055 is an apocalyptic number.

14053125114055 is a deficient number, since it is larger than the sum of its proper divisors (2820585901337).

14053125114055 is a wasteful number, since it uses less digits than its factorization.

14053125114055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1660146425.

The product of its (nonzero) digits is 60000, while the sum is 37.

Adding to 14053125114055 its reverse (55041152135041), we get a palindrome (69094277249096).

The spelling of 14053125114055 in words is "fourteen trillion, fifty-three billion, one hundred twenty-five million, one hundred fourteen thousand, fifty-five".

Divisors: 1 5 1693 8465 1660144727 8300723635 2810625022811 14053125114055