Base | Representation |
---|---|
bin | 101001111000011… |
… | …0111101101100010 |
3 | 10121221100122200011 |
4 | 1103300313231202 |
5 | 10334230220114 |
6 | 351240515134 |
7 | 46553010646 |
oct | 12360675542 |
9 | 3557318604 |
10 | 1405320034 |
11 | 6612a2818 |
12 | 33277baaa |
13 | 1951c2121 |
14 | d48d8c26 |
15 | 835961c4 |
hex | 53c37b62 |
1405320034 has 4 divisors (see below), whose sum is σ = 2107980054. Its totient is φ = 702660016.
The previous prime is 1405320029. The next prime is 1405320071. The reversal of 1405320034 is 4300235041.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4300235041 = 30431 ⋅141311.
It can be written as a sum of positive squares in only one way, i.e., 1368778009 + 36542025 = 36997^2 + 6045^2 .
It is a super-2 number, since 2×14053200342 = 3949848795923522312, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1405319987 and 1405320014.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 351330007 + ... + 351330010.
Almost surely, 21405320034 is an apocalyptic number.
1405320034 is a deficient number, since it is larger than the sum of its proper divisors (702660020).
1405320034 is an equidigital number, since it uses as much as digits as its factorization.
1405320034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 702660019.
The product of its (nonzero) digits is 1440, while the sum is 22.
The square root of 1405320034 is about 37487.5984026718. The cubic root of 1405320034 is about 1120.1041660132.
Adding to 1405320034 its reverse (4300235041), we get a palindrome (5705555075).
The spelling of 1405320034 in words is "one billion, four hundred five million, three hundred twenty thousand, thirty-four".
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