14053550153333 has 4 divisors (see below), whose sum is σ = 14057175008940. Its totient is φ = 14049925297728.

The previous prime is 14053550153327. The next prime is 14053550153341. The reversal of 14053550153333 is 33335105535041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8651263337809 + 5402286815524 = 2941303^2 + 2324282^2 .

It is a cyclic number.

It is not a de Polignac number, because 14053550153333 - 2¹⁰ = 14053550152309 is a prime.

It is a super-2 number, since 2×14053550153333² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14053550153033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1812421988 + ... + 1812429741.

It is an arithmetic number, because the mean of its divisors is an integer number (3514293752235).

Almost surely, 2^{14053550153333} is an apocalyptic number.

It is an amenable number.

14053550153333 is a deficient number, since it is larger than the sum of its proper divisors (3624855607).

14053550153333 is an equidigital number, since it uses as much as digits as its factorization.

14053550153333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3624855606.

The product of its (nonzero) digits is 607500, while the sum is 41.

Adding to 14053550153333 its reverse (33335105535041), we get a palindrome (47388655688374).

The spelling of 14053550153333 in words is "fourteen trillion, fifty-three billion, five hundred fifty million, one hundred fifty-three thousand, three hundred thirty-three".