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1405404145433 = 3447140770623
BaseRepresentation
bin10100011100111000100…
…111010110011100011001
311222100121000211211100102
4110130320213112130121
5141011231430123213
62553344520145145
7203352140063051
oct24347047263431
94870530754312
101405404145433
114a2035001792
121a84630081b5
13a26b53c8b72
144c044230561
15268577e8158
hex147389d6719

1405404145433 has 4 divisors (see below), whose sum is σ = 1405444950528. Its totient is φ = 1405363340340.

The previous prime is 1405404145421. The next prime is 1405404145441. The reversal of 1405404145433 is 3345414045041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1405404145433 - 222 = 1405399951129 is a prime.

It is a super-2 number, since 2×14054041454332 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1405404145493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20350841 + ... + 20419782.

It is an arithmetic number, because the mean of its divisors is an integer number (351361237632).

Almost surely, 21405404145433 is an apocalyptic number.

It is an amenable number.

1405404145433 is a deficient number, since it is larger than the sum of its proper divisors (40805095).

1405404145433 is an equidigital number, since it uses as much as digits as its factorization.

1405404145433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40805094.

The product of its (nonzero) digits is 230400, while the sum is 38.

The spelling of 1405404145433 in words is "one trillion, four hundred five billion, four hundred four million, one hundred forty-five thousand, four hundred thirty-three".

Divisors: 1 34471 40770623 1405404145433