14054053213411 has 4 divisors (see below), whose sum is σ = 14054993991000. Its totient is φ = 14053112435824.

The previous prime is 14054053213381. The next prime is 14054053213451. The reversal of 14054053213411 is 11431235045041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14054053213411 - 2⁵ = 14054053213379 is a prime.

It is a super-2 number, since 2×14054053213411² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14054053213451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 470366386 + ... + 470396263.

It is an arithmetic number, because the mean of its divisors is an integer number (3513748497750).

Almost surely, 2^{14054053213411} is an apocalyptic number.

14054053213411 is a deficient number, since it is larger than the sum of its proper divisors (940777589).

14054053213411 is an equidigital number, since it uses as much as digits as its factorization.

14054053213411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 940777588.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 14054053213411 its reverse (11431235045041), we get a palindrome (25485288258452).

The spelling of 14054053213411 in words is "fourteen trillion, fifty-four billion, fifty-three million, two hundred thirteen thousand, four hundred eleven".