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14055053523151 = 17826767854303
BaseRepresentation
bin1100110010000111001001…
…1110001111100011001111
31211202122112211211200220111
43030201302132033203033
53320234222200220101
645520445155100451
72650305220521004
oct314416236174317
954678484750814
1014055053523151
114529795332453
1216abb68ba1727
137ac502972454
143683a7dd38ab
1519590e26d251
hexcc87278f8cf

14055053523151 has 4 divisors (see below), whose sum is σ = 14881821377472. Its totient is φ = 13228285668832.

The previous prime is 14055053523143. The next prime is 14055053523179. The reversal of 14055053523151 is 15132535055041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14055053523151 - 23 = 14055053523143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14055053523751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 413383927135 + ... + 413383927168.

It is an arithmetic number, because the mean of its divisors is an integer number (3720455344368).

Almost surely, 214055053523151 is an apocalyptic number.

14055053523151 is a deficient number, since it is larger than the sum of its proper divisors (826767854321).

14055053523151 is an equidigital number, since it uses as much as digits as its factorization.

14055053523151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 826767854320.

The product of its (nonzero) digits is 225000, while the sum is 40.

Adding to 14055053523151 its reverse (15132535055041), we get a palindrome (29187588578192).

The spelling of 14055053523151 in words is "fourteen trillion, fifty-five billion, fifty-three million, five hundred twenty-three thousand, one hundred fifty-one".

Divisors: 1 17 826767854303 14055053523151