14055125200141 has 4 divisors (see below), whose sum is σ = 14055264374112. Its totient is φ = 14054986026172.

The previous prime is 14055125200063. The next prime is 14055125200187. The reversal of 14055125200141 is 14100252155041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14055125200141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14055125209141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69435391 + ... + 69637516.

It is an arithmetic number, because the mean of its divisors is an integer number (3513816093528).

Almost surely, 2^{14055125200141} is an apocalyptic number.

It is an amenable number.

14055125200141 is a deficient number, since it is larger than the sum of its proper divisors (139173971).

14055125200141 is a wasteful number, since it uses less digits than its factorization.

14055125200141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 139173970.

The product of its (nonzero) digits is 8000, while the sum is 31.

Adding to 14055125200141 its reverse (14100252155041), we get a palindrome (28155377355182).

The spelling of 14055125200141 in words is "fourteen trillion, fifty-five billion, one hundred twenty-five million, two hundred thousand, one hundred forty-one".