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14055325613 = 72007903659
BaseRepresentation
bin11010001011100001…
…10011111110101101
31100021112120112001022
431011300303332231
5212241130404423
610242410223525
71005206203460
oct150560637655
940245515038
1014055325613
115a6295718a
122883124ba5
13142cc10324
149749992d7
15573e10dc8
hex345c33fad

14055325613 has 4 divisors (see below), whose sum is σ = 16063229280. Its totient is φ = 12047421948.

The previous prime is 14055325561. The next prime is 14055325621. The reversal of 14055325613 is 31652355041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14055325613 - 26 = 14055325549 is a prime.

It is a super-3 number, since 3×140553256133 (a number of 31 digits) contains 333 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14055325913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1003951823 + ... + 1003951836.

It is an arithmetic number, because the mean of its divisors is an integer number (4015807320).

Almost surely, 214055325613 is an apocalyptic number.

It is an amenable number.

14055325613 is a deficient number, since it is larger than the sum of its proper divisors (2007903667).

14055325613 is an equidigital number, since it uses as much as digits as its factorization.

14055325613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2007903666.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 14055325613 in words is "fourteen billion, fifty-five million, three hundred twenty-five thousand, six hundred thirteen".

Divisors: 1 7 2007903659 14055325613