Base | Representation |
---|---|
bin | 11010001011100010… |
… | …01110001110101011 |
3 | 1100021112202222112110 |
4 | 31011301032032223 |
5 | 212241142330011 |
6 | 10242412413403 |
7 | 1005210132105 |
oct | 150561161653 |
9 | 40245688473 |
10 | 14055433131 |
11 | 5a62a1aa43 |
12 | 2883177263 |
13 | 142cc4a24c |
14 | 9749c6575 |
15 | 573e32ba6 |
hex | 345c4e3ab |
14055433131 has 4 divisors (see below), whose sum is σ = 18740577512. Its totient is φ = 9370288752.
The previous prime is 14055433099. The next prime is 14055433153. The reversal of 14055433131 is 13133455041.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14055433131 - 25 = 14055433099 is a prime.
It is a super-2 number, since 2×140554331312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14055633131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2342572186 + ... + 2342572191.
It is an arithmetic number, because the mean of its divisors is an integer number (4685144378).
Almost surely, 214055433131 is an apocalyptic number.
14055433131 is a deficient number, since it is larger than the sum of its proper divisors (4685144381).
14055433131 is an equidigital number, since it uses as much as digits as its factorization.
14055433131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4685144380.
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 14055433131 its reverse (13133455041), we get a palindrome (27188888172).
The spelling of 14055433131 in words is "fourteen billion, fifty-five million, four hundred thirty-three thousand, one hundred thirty-one".
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