Base | Representation |
---|---|
bin | 1100110010001000110111… |
… | …0001011111101111100001 |
3 | 1211202200201202201010112120 |
4 | 3030202031301133233201 |
5 | 3320241141424230131 |
6 | 45521002440214453 |
7 | 2650322451651645 |
oct | 314421561375741 |
9 | 54680652633476 |
10 | 14055511555041 |
11 | 45299aa934600 |
12 | 16b007646a429 |
13 | 7ac576821c38 |
14 | 36840cb82c25 |
15 | 195939596496 |
hex | cc88dc5fbe1 |
14055511555041 has 24 divisors (see below), whose sum is σ = 21101683163232. Its totient is φ = 8310723748800.
The previous prime is 14055511555021. The next prime is 14055511555087.
14055511555041 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 14055511555041 - 26 = 14055511554977 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 14055511554984 and 14055511555002.
It is not an unprimeable number, because it can be changed into a prime (14055511555021) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 472185331 + ... + 472215096.
It is an arithmetic number, because the mean of its divisors is an integer number (879236798468).
Almost surely, 214055511555041 is an apocalyptic number.
14055511555041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
14055511555041 is a deficient number, since it is larger than the sum of its proper divisors (7046171608191).
14055511555041 is a wasteful number, since it uses less digits than its factorization.
14055511555041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 944400493 (or 944400482 counting only the distinct ones).
The product of its (nonzero) digits is 250000, while the sum is 42.
The spelling of 14055511555041 in words is "fourteen trillion, fifty-five billion, five hundred eleven million, five hundred fifty-five thousand, forty-one".
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