Base | Representation |
---|---|
bin | 1000001011110100011… |
… | …0111000110000101011 |
3 | 111102221110122001110002 |
4 | 2002331012320300223 |
5 | 4300433040341101 |
6 | 144332431413215 |
7 | 13105326220121 |
oct | 2027506706053 |
9 | 442843561402 |
10 | 140611652651 |
11 | 546a66808a8 |
12 | 2330268420b |
13 | 1034b50a742 |
14 | 6b3c969911 |
15 | 39ce791d6b |
hex | 20bd1b8c2b |
140611652651 has 4 divisors (see below), whose sum is σ = 142305769032. Its totient is φ = 138917536272.
The previous prime is 140611652641. The next prime is 140611652663. The reversal of 140611652651 is 156256116041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140611652651 is a prime.
It is a super-2 number, since 2×1406116526512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140611652641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 847058066 + ... + 847058231.
It is an arithmetic number, because the mean of its divisors is an integer number (35576442258).
Almost surely, 2140611652651 is an apocalyptic number.
140611652651 is a deficient number, since it is larger than the sum of its proper divisors (1694116381).
140611652651 is an equidigital number, since it uses as much as digits as its factorization.
140611652651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1694116380.
The product of its (nonzero) digits is 43200, while the sum is 38.
Adding to 140611652651 its reverse (156256116041), we get a palindrome (296867768692).
The spelling of 140611652651 in words is "one hundred forty billion, six hundred eleven million, six hundred fifty-two thousand, six hundred fifty-one".
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