Base | Representation |
---|---|
bin | 11010001100111101… |
… | …00010001101010001 |
3 | 1100022101010110111212 |
4 | 31012132202031101 |
5 | 212302212431231 |
6 | 10243515145505 |
7 | 1005413113541 |
oct | 150636421521 |
9 | 40271113455 |
10 | 14067311441 |
11 | 5a696a3327 |
12 | 2887145295 |
13 | 1432548a31 |
14 | 9763d9321 |
15 | 574ecc42b |
hex | 3467a2351 |
14067311441 has 4 divisors (see below), whose sum is σ = 14067731892. Its totient is φ = 14066890992.
The previous prime is 14067311429. The next prime is 14067311473. The reversal of 14067311441 is 14411376041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7207330816 + 6859980625 = 84896^2 + 82825^2 .
It is a cyclic number.
It is not a de Polignac number, because 14067311441 - 214 = 14067295057 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 14067311398 and 14067311407.
It is not an unprimeable number, because it can be changed into a prime (14067313441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155246 + ... + 228551.
It is an arithmetic number, because the mean of its divisors is an integer number (3516932973).
Almost surely, 214067311441 is an apocalyptic number.
It is an amenable number.
14067311441 is a deficient number, since it is larger than the sum of its proper divisors (420451).
14067311441 is an equidigital number, since it uses as much as digits as its factorization.
14067311441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 420450.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 14067311441 its reverse (14411376041), we get a palindrome (28478687482).
The spelling of 14067311441 in words is "fourteen billion, sixty-seven million, three hundred eleven thousand, four hundred forty-one".
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