Base | Representation |
---|---|
bin | 10100011110011010111… |
… | …101011110100101111111 |
3 | 11222111212000112212112220 |
4 | 110132122331132211333 |
5 | 141023121323110101 |
6 | 2554220340500423 |
7 | 203441053424421 |
oct | 24363275364577 |
9 | 4874760485486 |
10 | 1407054113151 |
11 | 4a2801401975 |
12 | 1a88436aa713 |
13 | a28b91a841b |
14 | 4c15d410811 |
15 | 269025b7636 |
hex | 1479af5e97f |
1407054113151 has 4 divisors (see below), whose sum is σ = 1876072150872. Its totient is φ = 938036075432.
The previous prime is 1407054113137. The next prime is 1407054113173. The reversal of 1407054113151 is 1513114507041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1407054113151 - 222 = 1407049918847 is a prime.
It is a super-2 number, since 2×14070541131512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1407054117151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234509018856 + ... + 234509018861.
It is an arithmetic number, because the mean of its divisors is an integer number (469018037718).
Almost surely, 21407054113151 is an apocalyptic number.
1407054113151 is a deficient number, since it is larger than the sum of its proper divisors (469018037721).
1407054113151 is an equidigital number, since it uses as much as digits as its factorization.
1407054113151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 469018037720.
The product of its (nonzero) digits is 8400, while the sum is 33.
The spelling of 1407054113151 in words is "one trillion, four hundred seven billion, fifty-four million, one hundred thirteen thousand, one hundred fifty-one".
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