14083117737607 has 4 divisors (see below), whose sum is σ = 14426608414176. Its totient is φ = 13739627061040.

The previous prime is 14083117737571. The next prime is 14083117737673. The reversal of 14083117737607 is 70673771138041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14083117737607 is a prime.

It is a super-2 number, since 2×14083117737607² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14083117737407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171745338223 + ... + 171745338304.

It is an arithmetic number, because the mean of its divisors is an integer number (3606652103544).

Almost surely, 2^{14083117737607} is an apocalyptic number.

14083117737607 is a deficient number, since it is larger than the sum of its proper divisors (343490676569).

14083117737607 is an equidigital number, since it uses as much as digits as its factorization.

14083117737607 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 343490676568.

The product of its (nonzero) digits is 4148928, while the sum is 55.

The spelling of 14083117737607 in words is "fourteen trillion, eighty-three billion, one hundred seventeen million, seven hundred thirty-seven thousand, six hundred seven".