Base | Representation |
---|---|
bin | 11010010000100100… |
… | …11001001010111011 |
3 | 1100101111021111122021 |
4 | 31020102121022323 |
5 | 212333001330011 |
6 | 10250522135311 |
7 | 1006232221000 |
oct | 151022311273 |
9 | 40344244567 |
10 | 14097683131 |
11 | 5a84857aa4 |
12 | 2895351537 |
13 | 1438920c4c |
14 | 97a4638a7 |
15 | 5779cb471 |
hex | 3484992bb |
14097683131 has 32 divisors (see below), whose sum is σ = 17117206400. Its totient is φ = 11595322368.
The previous prime is 14097683129. The next prime is 14097683183. The reversal of 14097683131 is 13138679041.
It is not a de Polignac number, because 14097683131 - 21 = 14097683129 is a prime.
It is a super-4 number, since 4×140976831314 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a hoax number, since the sum of its digits (43) coincides with the sum of the digits of its distinct prime factors.
It is not an unprimeable number, because it can be changed into a prime (14097683111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 918835 + ... + 934051.
It is an arithmetic number, because the mean of its divisors is an integer number (534912700).
Almost surely, 214097683131 is an apocalyptic number.
14097683131 is a deficient number, since it is larger than the sum of its proper divisors (3019523269).
14097683131 is an equidigital number, since it uses as much as digits as its factorization.
14097683131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15348 (or 15334 counting only the distinct ones).
The product of its (nonzero) digits is 108864, while the sum is 43.
The spelling of 14097683131 in words is "fourteen billion, ninety-seven million, six hundred eighty-three thousand, one hundred thirty-one".
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