141001201343041 has 8 divisors (see below), whose sum is σ = 151873320479720. Its totient is φ = 130132778332032.

The previous prime is 141001201343029. The next prime is 141001201343111. The reversal of 141001201343041 is 140343102100141.

It can be written as a sum of positive squares in 4 ways, for example, as 15975169641025 + 125026031702016 = 3996895^2 + 11181504^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141001201343041 - 2¹³ = 141001201334849 is a prime.

It is a super-3 number, since 3×141001201343041³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141001201342997 and 141001201343015.

It is not an unprimeable number, because it can be changed into a prime (141001201343441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 923952180 + ... + 924104773.

It is an arithmetic number, because the mean of its divisors is an integer number (18984165059965).

Almost surely, 2^{141001201343041} is an apocalyptic number.

It is an amenable number.

141001201343041 is a deficient number, since it is larger than the sum of its proper divisors (10872119136679).

141001201343041 is a wasteful number, since it uses less digits than its factorization.

141001201343041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1848062835.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 141001201343041 its reverse (140343102100141), we get a palindrome (281344303443182).

The spelling of 141001201343041 in words is "one hundred forty-one trillion, one billion, two hundred one million, three hundred forty-three thousand, forty-one".