1410020113 has 4 divisors (see below), whose sum is σ = 1410973668. Its totient is φ = 1409066560.

The previous prime is 1410020099. The next prime is 1410020179. The reversal of 1410020113 is 3110200141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 381342784 + 1028677329 = 19528^2 + 32073^2 .

It is a cyclic number.

It is not a de Polignac number, because 1410020113 - 2⁵ = 1410020081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1410020093 and 1410020102.

It is not an unprimeable number, because it can be changed into a prime (1410021113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 474556 + ... + 477517.

It is an arithmetic number, because the mean of its divisors is an integer number (352743417).

Almost surely, 2^1410020113 is an apocalyptic number.

It is an amenable number.

1410020113 is a deficient number, since it is larger than the sum of its proper divisors (953555).

1410020113 is an equidigital number, since it uses as much as digits as its factorization.

1410020113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 953554.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1410020113 is about 37550.2345265645. The cubic root of 1410020113 is about 1121.3515022575.

Adding to 1410020113 its reverse (3110200141), we get a palindrome (4520220254).

The spelling of 1410020113 in words is "one billion, four hundred ten million, twenty thousand, one hundred thirteen".