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141002341231 = 466813020551
BaseRepresentation
bin1000001101010001100…
…1001111101101101111
3111110221200210002102111
42003110121033231233
54302233044404411
6144435305304451
713121112060643
oct2032431175557
9443850702374
10141002341231
1154887166a24
12233b1495127
13103b143ba0b
146b787c8c23
153a03c16721
hex20d464fb6f

141002341231 has 4 divisors (see below), whose sum is σ = 141005408464. Its totient is φ = 140999274000.

The previous prime is 141002341229. The next prime is 141002341243. The reversal of 141002341231 is 132143200141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141002341231 - 21 = 141002341229 is a prime.

It is a super-2 number, since 2×1410023412312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141002341261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1463595 + ... + 1556956.

It is an arithmetic number, because the mean of its divisors is an integer number (35251352116).

Almost surely, 2141002341231 is an apocalyptic number.

141002341231 is a deficient number, since it is larger than the sum of its proper divisors (3067233).

141002341231 is an equidigital number, since it uses as much as digits as its factorization.

141002341231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3067232.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 141002341231 its reverse (132143200141), we get a palindrome (273145541372).

The spelling of 141002341231 in words is "one hundred forty-one billion, two million, three hundred forty-one thousand, two hundred thirty-one".

Divisors: 1 46681 3020551 141002341231