14100251341045 has 4 divisors (see below), whose sum is σ = 16920301609260. Its totient is φ = 11280201072832.

The previous prime is 14100251341031. The next prime is 14100251341073. The reversal of 14100251341045 is 54014315200141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4779741532644 + 9320509808401 = 2186262^2 + 3052951^2 .

It is a cyclic number.

It is not a de Polignac number, because 14100251341045 - 2³³ = 14091661406453 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14100251340998 and 14100251341016.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1410025134100 + ... + 1410025134109.

It is an arithmetic number, because the mean of its divisors is an integer number (4230075402315).

Almost surely, 2^{14100251341045} is an apocalyptic number.

It is an amenable number.

14100251341045 is a deficient number, since it is larger than the sum of its proper divisors (2820050268215).

14100251341045 is an equidigital number, since it uses as much as digits as its factorization.

14100251341045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2820050268214.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 14100251341045 its reverse (54014315200141), we get a palindrome (68114566541186).

The spelling of 14100251341045 in words is "fourteen trillion, one hundred billion, two hundred fifty-one million, three hundred forty-one thousand, forty-five".