Base | Representation |
---|---|
bin | 10100100001001100011… |
… | …011011000111001001001 |
3 | 11222210112112001212202202 |
4 | 110201030123120321021 |
5 | 141100221032140403 |
6 | 2555432021005545 |
7 | 203604616115000 |
oct | 24411433307111 |
9 | 4883475055682 |
10 | 1410031521353 |
11 | 4a3a9a041804 |
12 | 1a93348538b5 |
13 | a2c71cac920 |
14 | 4c362a15c37 |
15 | 26a28b97688 |
hex | 1484c6d8e49 |
1410031521353 has 64 divisors (see below), whose sum is σ = 1784487936000. Its totient is φ = 1107053801280.
The previous prime is 1410031521323. The next prime is 1410031521377. The reversal of 1410031521353 is 3531251300141.
It is a de Polignac number, because none of the positive numbers 2k-1410031521353 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1410031521323) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 667943768 + ... + 667945878.
It is an arithmetic number, because the mean of its divisors is an integer number (27882624000).
Almost surely, 21410031521353 is an apocalyptic number.
1410031521353 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1410031521353 is a deficient number, since it is larger than the sum of its proper divisors (374456414647).
1410031521353 is a wasteful number, since it uses less digits than its factorization.
1410031521353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3227 (or 3213 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 1410031521353 its reverse (3531251300141), we get a palindrome (4941282821494).
The spelling of 1410031521353 in words is "one trillion, four hundred ten billion, thirty-one million, five hundred twenty-one thousand, three hundred fifty-three".
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