141003231231 has 4 divisors (see below), whose sum is σ = 188004308312. Its totient is φ = 94002154152.

The previous prime is 141003231211. The next prime is 141003231251. The reversal of 141003231231 is 132132300141.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (141003231211) and next prime (141003231251).

It is not a de Polignac number, because 141003231231 - 2¹⁷ = 141003100159 is a prime.

It is a super-2 number, since 2×141003231231² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141003231198 and 141003231207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141003231211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23500538536 + ... + 23500538541.

It is an arithmetic number, because the mean of its divisors is an integer number (47001077078).

Almost surely, 2^141003231231 is an apocalyptic number.

141003231231 is a deficient number, since it is larger than the sum of its proper divisors (47001077081).

141003231231 is an equidigital number, since it uses as much as digits as its factorization.

141003231231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47001077080.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 141003231231 its reverse (132132300141), we get a palindrome (273135531372).

The spelling of 141003231231 in words is "one hundred forty-one billion, three million, two hundred thirty-one thousand, two hundred thirty-one".