Base | Representation |
---|---|
bin | 11010010000111001… |
… | …00010011010100001 |
3 | 1100101200021121111221 |
4 | 31020130202122201 |
5 | 212334141424213 |
6 | 10251055135041 |
7 | 1006263635032 |
oct | 151034423241 |
9 | 40350247457 |
10 | 14100342433 |
11 | 5a86303a71 |
12 | 2896214481 |
13 | 14393424b8 |
14 | 97a956a89 |
15 | 577d5438d |
hex | 3487226a1 |
14100342433 has 4 divisors (see below), whose sum is σ = 14102414640. Its totient is φ = 14098270228.
The previous prime is 14100342427. The next prime is 14100342493. The reversal of 14100342433 is 33424300141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33424300141 = 28463 ⋅1174307.
It is a cyclic number.
It is not a de Polignac number, because 14100342433 - 233 = 5510407841 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14100342398 and 14100342407.
It is not an unprimeable number, because it can be changed into a prime (14100342493) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1025863 + ... + 1039516.
It is an arithmetic number, because the mean of its divisors is an integer number (3525603660).
Almost surely, 214100342433 is an apocalyptic number.
It is an amenable number.
14100342433 is a deficient number, since it is larger than the sum of its proper divisors (2072207).
14100342433 is an equidigital number, since it uses as much as digits as its factorization.
14100342433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2072206.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 14100342433 its reverse (33424300141), we get a palindrome (47524642574).
The spelling of 14100342433 in words is "fourteen billion, one hundred million, three hundred forty-two thousand, four hundred thirty-three".
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