141004121521 has 4 divisors (see below), whose sum is σ = 141004987200. Its totient is φ = 141003255844.

The previous prime is 141004121483. The next prime is 141004121539. The reversal of 141004121521 is 125121400141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 125121400141 = 479 ⋅261213779.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141004121521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141004121492 and 141004121501.

It is not an unprimeable number, because it can be changed into a prime (141004121551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106501 + ... + 541618.

It is an arithmetic number, because the mean of its divisors is an integer number (35251246800).

Almost surely, 2^141004121521 is an apocalyptic number.

It is an amenable number.

141004121521 is a deficient number, since it is larger than the sum of its proper divisors (865679).

141004121521 is an equidigital number, since it uses as much as digits as its factorization.

141004121521 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 865678.

The product of its (nonzero) digits is 320, while the sum is 22.

Adding to 141004121521 its reverse (125121400141), we get a palindrome (266125521662).

The spelling of 141004121521 in words is "one hundred forty-one billion, four million, one hundred twenty-one thousand, five hundred twenty-one".