14101017554201 has 4 divisors (see below), whose sum is σ = 14131212453072. Its totient is φ = 14070822655332.

The previous prime is 14101017554167. The next prime is 14101017554207. The reversal of 14101017554201 is 10245571010141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14101017554201 - 2⁶ = 14101017554137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14101017554207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15097448735 + ... + 15097449668.

It is an arithmetic number, because the mean of its divisors is an integer number (3532803113268).

Almost surely, 2^{14101017554201} is an apocalyptic number.

It is an amenable number.

14101017554201 is a deficient number, since it is larger than the sum of its proper divisors (30194898871).

14101017554201 is an equidigital number, since it uses as much as digits as its factorization.

14101017554201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30194898870.

The product of its (nonzero) digits is 5600, while the sum is 32.

Adding to 14101017554201 its reverse (10245571010141), we get a palindrome (24346588564342).

The spelling of 14101017554201 in words is "fourteen trillion, one hundred one billion, seventeen million, five hundred fifty-four thousand, two hundred one".