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14101043155 = 52820208631
BaseRepresentation
bin11010010000111110…
…01101011111010011
31100101201121012201121
431020133031133103
5212334331340110
610251122143111
71006302613663
oct151037153723
940351535647
1014101043155
115a86742481
1228964b1a97
131439529424
1497aa9a1a3
15577e41cda
hex3487cd7d3

14101043155 has 4 divisors (see below), whose sum is σ = 16921251792. Its totient is φ = 11280834520.

The previous prime is 14101043153. The next prime is 14101043167. The reversal of 14101043155 is 55134010141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55134010141 = 77876287163.

It is not a de Polignac number, because 14101043155 - 21 = 14101043153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14101043153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1410104311 + ... + 1410104320.

It is an arithmetic number, because the mean of its divisors is an integer number (4230312948).

Almost surely, 214101043155 is an apocalyptic number.

14101043155 is a deficient number, since it is larger than the sum of its proper divisors (2820208637).

14101043155 is an equidigital number, since it uses as much as digits as its factorization.

14101043155 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2820208636.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 14101043155 its reverse (55134010141), we get a palindrome (69235053296).

The spelling of 14101043155 in words is "fourteen billion, one hundred one million, forty-three thousand, one hundred fifty-five".

Divisors: 1 5 2820208631 14101043155