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14101214115 = 353791927647
BaseRepresentation
bin11010010000111111…
…10111001110100011
31100101201220220020110
431020133313032203
5212334402322430
610251125542403
71006304225262
oct151037671643
940351826213
1014101214115
115a8684996a
122896574a03
1314395891a1
1497ab025d9
15577e777b0
hex3487f73a3

14101214115 has 32 divisors (see below), whose sum is σ = 23197777920. Its totient is φ = 7309160064.

The previous prime is 14101214089. The next prime is 14101214119. The reversal of 14101214115 is 51141210141.

It is not a de Polignac number, because 14101214115 - 26 = 14101214051 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14101214091 and 14101214100.

It is not an unprimeable number, because it can be changed into a prime (14101214119) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 496222 + ... + 523868.

It is an arithmetic number, because the mean of its divisors is an integer number (724930560).

Almost surely, 214101214115 is an apocalyptic number.

14101214115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

14101214115 is a deficient number, since it is larger than the sum of its proper divisors (9096563805).

14101214115 is a wasteful number, since it uses less digits than its factorization.

14101214115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28611.

The product of its (nonzero) digits is 160, while the sum is 21.

Adding to 14101214115 its reverse (51141210141), we get a palindrome (65242424256).

The spelling of 14101214115 in words is "fourteen billion, one hundred one million, two hundred fourteen thousand, one hundred fifteen".

Divisors: 1 3 5 15 37 111 185 555 919 2757 4595 13785 27647 34003 82941 102009 138235 170015 414705 510045 1022939 3068817 5114695 15344085 25407593 76222779 127037965 381113895 940080941 2820242823 4700404705 14101214115