1410130125121 has 3 divisors (see below), whose sum is σ = 1410131312611. Its totient is φ = 1410128937632.

The previous prime is 1410130125119. The next prime is 1410130125191. The reversal of 1410130125121 is 1215210310141.

The square root of 1410130125121 is 1187489.

It is a perfect power (a square), and thus also a powerful number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in only one way, i.e., 660174125121 + 749956000000 = 812511^2 + 866000^2 .

It is not a de Polignac number, because 1410130125121 - 2¹ = 1410130125119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1410130125092 and 1410130125101.

It is not an unprimeable number, because it can be changed into a prime (1410130125191) by changing a digit.

It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 593745 + ... + 1781233.

Almost surely, 2^{1410130125121} is an apocalyptic number.

1410130125121 is the 1187489-th square number.

1410130125121 is the 593745-th centered octagonal number.

It is an amenable number.

1410130125121 is a deficient number, since it is larger than the sum of its proper divisors (1187490).

1410130125121 is an frugal number, since it uses more digits than its factorization.

1410130125121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2374978 (or 1187489 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 1410130125121 its reverse (1215210310141), we get a palindrome (2625340435262).

The spelling of 1410130125121 in words is "one trillion, four hundred ten billion, one hundred thirty million, one hundred twenty-five thousand, one hundred twenty-one".