14102113131 has 12 divisors (see below), whose sum is σ = 20372046552. Its totient is φ = 9400334496.

The previous prime is 14102113099. The next prime is 14102113133. The reversal of 14102113131 is 13131120141.

It is a happy number.

14102113131 is a `hidden beast` number, since 141 + 0 + 211 + 313 + 1 = 666.

14102113131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 14102113131 - 2⁵ = 14102113099 is a prime.

It is a super-2 number, since 2×14102113131² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14102113133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1866 + ... + 167951.

It is an arithmetic number, because the mean of its divisors is an integer number (1697670546).

Almost surely, 2^14102113131 is an apocalyptic number.

14102113131 is a deficient number, since it is larger than the sum of its proper divisors (6269933421).

14102113131 is a wasteful number, since it uses less digits than its factorization.

14102113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 179050 (or 179047 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 14102113131 its reverse (13131120141), we get a palindrome (27233233272).

The spelling of 14102113131 in words is "fourteen billion, one hundred two million, one hundred thirteen thousand, one hundred thirty-one".