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14103023527 = 61231197107
BaseRepresentation
bin11010010001001101…
…10000111110100111
31100101212022211021201
431020212300332213
5212340333223102
610251232423331
71006325502445
oct151046607647
940355284251
1014103023527
115a8787534a
1228970a7b47
131439a70948
1497b053b95
155781d3987
hex3489b0fa7

14103023527 has 4 divisors (see below), whose sum is σ = 14334220696. Its totient is φ = 13871826360.

The previous prime is 14103023509. The next prime is 14103023567. The reversal of 14103023527 is 72532030141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14103023527 - 223 = 14094634919 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14103023495 and 14103023504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14103023567) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115598493 + ... + 115598614.

It is an arithmetic number, because the mean of its divisors is an integer number (3583555174).

Almost surely, 214103023527 is an apocalyptic number.

14103023527 is a deficient number, since it is larger than the sum of its proper divisors (231197169).

14103023527 is an equidigital number, since it uses as much as digits as its factorization.

14103023527 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231197168.

The product of its (nonzero) digits is 5040, while the sum is 28.

Adding to 14103023527 its reverse (72532030141), we get a palindrome (86635053668).

The spelling of 14103023527 in words is "fourteen billion, one hundred three million, twenty-three thousand, five hundred twenty-seven".

Divisors: 1 61 231197107 14103023527