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14103111220111 = 85371651998503
BaseRepresentation
bin1100110100111010001011…
…1011110011101110001111
31211221020121001212122122201
43031032202323303232033
53322031132433020421
645554514014222331
72653626146304454
oct315164273635617
954836531778581
1014103111220111
114548106686481
1216b933b4b49a7
137b3bc11b9724
1436a8467a782b
15196cc334ab91
hexcd3a2ef3b8f

14103111220111 has 4 divisors (see below), whose sum is σ = 14104763227152. Its totient is φ = 14101459213072.

The previous prime is 14103111220097. The next prime is 14103111220117. The reversal of 14103111220111 is 11102211130141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14103111220111 - 27 = 14103111219983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14103111220117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 825990715 + ... + 826007788.

It is an arithmetic number, because the mean of its divisors is an integer number (3526190806788).

Almost surely, 214103111220111 is an apocalyptic number.

14103111220111 is a deficient number, since it is larger than the sum of its proper divisors (1652007041).

14103111220111 is an equidigital number, since it uses as much as digits as its factorization.

14103111220111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1652007040.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 14103111220111 its reverse (11102211130141), we get a palindrome (25205322350252).

The spelling of 14103111220111 in words is "fourteen trillion, one hundred three billion, one hundred eleven million, two hundred twenty thousand, one hundred eleven".

Divisors: 1 8537 1651998503 14103111220111