Base | Representation |
---|---|
bin | 1100110100111011011010… |
… | …0110010010001011011011 |
3 | 1211221021110001122101222121 |
4 | 3031032312212102023123 |
5 | 3322032321411401021 |
6 | 45555010441202111 |
7 | 2653640263363543 |
oct | 315166646221333 |
9 | 54837401571877 |
10 | 14103441122011 |
11 | 454826592367a |
12 | 16b9411a90337 |
13 | 7b3c44656957 |
14 | 36a878522323 |
15 | 196ce22b4741 |
hex | cd3b69922db |
14103441122011 has 4 divisors (see below), whose sum is σ = 14243079153024. Its totient is φ = 13963803091000.
The previous prime is 14103441121993. The next prime is 14103441122047. The reversal of 14103441122011 is 11022114430141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14103441122011 - 217 = 14103440990939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14103441122051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69819015355 + ... + 69819015556.
It is an arithmetic number, because the mean of its divisors is an integer number (3560769788256).
Almost surely, 214103441122011 is an apocalyptic number.
14103441122011 is a deficient number, since it is larger than the sum of its proper divisors (139638031013).
14103441122011 is a wasteful number, since it uses less digits than its factorization.
14103441122011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139638031012.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 14103441122011 its reverse (11022114430141), we get a palindrome (25125555552152).
The spelling of 14103441122011 in words is "fourteen trillion, one hundred three billion, four hundred forty-one million, one hundred twenty-two thousand, eleven".
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