Base | Representation |
---|---|
bin | 11010010001010001… |
… | …10010000111010111 |
3 | 1100101220022200212020 |
4 | 31020220302013113 |
5 | 212341002134341 |
6 | 10251252024223 |
7 | 1006333134531 |
oct | 151050620727 |
9 | 40356280766 |
10 | 14103552471 |
11 | 5a880a6798 |
12 | 2897302073 |
13 | 1439bc7628 |
14 | 97b150851 |
15 | 57828a566 |
hex | 348a321d7 |
14103552471 has 4 divisors (see below), whose sum is σ = 18804736632. Its totient is φ = 9402368312.
The previous prime is 14103552457. The next prime is 14103552479. The reversal of 14103552471 is 17425530141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14103552471 - 211 = 14103550423 is a prime.
It is a super-3 number, since 3×141035524713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14103552479) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2350592076 + ... + 2350592081.
It is an arithmetic number, because the mean of its divisors is an integer number (4701184158).
Almost surely, 214103552471 is an apocalyptic number.
14103552471 is a deficient number, since it is larger than the sum of its proper divisors (4701184161).
14103552471 is an equidigital number, since it uses as much as digits as its factorization.
14103552471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4701184160.
The product of its (nonzero) digits is 16800, while the sum is 33.
The spelling of 14103552471 in words is "fourteen billion, one hundred three million, five hundred fifty-two thousand, four hundred seventy-one".
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