141040331134231 has 4 divisors (see below), whose sum is σ = 143352467710264. Its totient is φ = 138728194558200.

The previous prime is 141040331134229. The next prime is 141040331134247. The reversal of 141040331134231 is 132431133040141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141040331134231 - 2¹ = 141040331134229 is a prime.

It is a super-3 number, since 3×141040331134231³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141040331134193 and 141040331134202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141040331174231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1156068287925 + ... + 1156068288046.

It is an arithmetic number, because the mean of its divisors is an integer number (35838116927566).

Almost surely, 2^{141040331134231} is an apocalyptic number.

141040331134231 is a deficient number, since it is larger than the sum of its proper divisors (2312136576033).

141040331134231 is an equidigital number, since it uses as much as digits as its factorization.

141040331134231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2312136576032.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 141040331134231 its reverse (132431133040141), we get a palindrome (273471464174372).

The spelling of 141040331134231 in words is "one hundred forty-one trillion, forty billion, three hundred thirty-one million, one hundred thirty-four thousand, two hundred thirty-one".