141054411326117 has 16 divisors (see below), whose sum is σ = 152825817450240. Its totient is φ = 129669046950912.

The previous prime is 141054411326047. The next prime is 141054411326197. The reversal of 141054411326117 is 711623114450141.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141054411326117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141054411326197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 190662308 + ... + 191400690.

It is an arithmetic number, because the mean of its divisors is an integer number (9551613590640).

Almost surely, 2^{141054411326117} is an apocalyptic number.

141054411326117 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

It is an amenable number.

141054411326117 is a deficient number, since it is larger than the sum of its proper divisors (11771406124123).

141054411326117 is a wasteful number, since it uses less digits than its factorization.

141054411326117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 999772.

The product of its (nonzero) digits is 80640, while the sum is 41.

Adding to 141054411326117 its reverse (711623114450141), we get a palindrome (852677525776258).

The spelling of 141054411326117 in words is "one hundred forty-one trillion, fifty-four billion, four hundred eleven million, three hundred twenty-six thousand, one hundred seventeen".