Base | Representation |
---|---|
bin | 1100110101010011111000… |
… | …1101001001111011101111 |
3 | 1211221220101221102010012001 |
4 | 3031110332031021323233 |
5 | 3322134300332001221 |
6 | 50002014420553131 |
7 | 2654262142221532 |
oct | 315247615117357 |
9 | 54856357363161 |
10 | 14110011203311 |
11 | 4550027527a31 |
12 | 16ba7462527a7 |
13 | 7b475087431a |
14 | 36acdcd2aa19 |
15 | 197078eaa391 |
hex | cd53e349eef |
14110011203311 has 4 divisors (see below), whose sum is σ = 14596563313800. Its totient is φ = 13623459092824.
The previous prime is 14110011203293. The next prime is 14110011203359. The reversal of 14110011203311 is 11330211001141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14110011203311 - 221 = 14110009106159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14110011201311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243276055201 + ... + 243276055258.
It is an arithmetic number, because the mean of its divisors is an integer number (3649140828450).
Almost surely, 214110011203311 is an apocalyptic number.
14110011203311 is a deficient number, since it is larger than the sum of its proper divisors (486552110489).
14110011203311 is an equidigital number, since it uses as much as digits as its factorization.
14110011203311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 486552110488.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 14110011203311 its reverse (11330211001141), we get a palindrome (25440222204452).
The spelling of 14110011203311 in words is "fourteen trillion, one hundred ten billion, eleven million, two hundred three thousand, three hundred eleven".
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