14110011213031 has 4 divisors (see below), whose sum is σ = 14120096998000. Its totient is φ = 14099925428064.

The previous prime is 14110011213029. The next prime is 14110011213037. The reversal of 14110011213031 is 13031211001141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14110011213031 - 2¹ = 14110011213029 is a prime.

It is a super-2 number, since 2×14110011213031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14110011213037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5042890386 + ... + 5042893183.

It is an arithmetic number, because the mean of its divisors is an integer number (3530024249500).

Almost surely, 2^{14110011213031} is an apocalyptic number.

14110011213031 is a deficient number, since it is larger than the sum of its proper divisors (10085784969).

14110011213031 is a wasteful number, since it uses less digits than its factorization.

14110011213031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10085784968.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 14110011213031 its reverse (13031211001141), we get a palindrome (27141222214172).

The spelling of 14110011213031 in words is "fourteen trillion, one hundred ten billion, eleven million, two hundred thirteen thousand, thirty-one".