Base | Representation |
---|---|
bin | 1000001101101001000… |
… | …1111110110001100101 |
3 | 111111012120121120011121 |
4 | 2003122101332301211 |
5 | 4302433340201013 |
6 | 144453154133541 |
7 | 13123421363530 |
oct | 2033221766145 |
9 | 444176546147 |
10 | 141101100133 |
11 | 5492798aa54 |
12 | 2341a5812b1 |
13 | 103c8a39636 |
14 | 6b87975a17 |
15 | 3a0c72358d |
hex | 20da47ec65 |
141101100133 has 16 divisors (see below), whose sum is σ = 166833792000. Its totient is φ = 116762994432.
The previous prime is 141101100131. The next prime is 141101100163. The reversal of 141101100133 is 331001101141.
141101100133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 141101100133 - 21 = 141101100131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141101100131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3007308 + ... + 3053866.
It is an arithmetic number, because the mean of its divisors is an integer number (10427112000).
Almost surely, 2141101100133 is an apocalyptic number.
It is an amenable number.
141101100133 is a deficient number, since it is larger than the sum of its proper divisors (25732691867).
141101100133 is a wasteful number, since it uses less digits than its factorization.
141101100133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61524.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 141101100133 its reverse (331001101141), we get a palindrome (472102201274).
The spelling of 141101100133 in words is "one hundred forty-one billion, one hundred one million, one hundred thousand, one hundred thirty-three".
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