Base | Representation |
---|---|
bin | 10100100010000111111… |
… | …101111101110101111101 |
3 | 11222220010010201021101100 |
4 | 110202013331331311331 |
5 | 141104242243110331 |
6 | 3000115103203313 |
7 | 203641435600113 |
oct | 24420775756575 |
9 | 4886103637340 |
10 | 1411030441341 |
11 | 4a4461998114 |
12 | 1a95732a6539 |
13 | a30a0c2c341 |
14 | 4c419561ab3 |
15 | 26a86713ae6 |
hex | 14887f7dd7d |
1411030441341 has 12 divisors (see below), whose sum is σ = 2103902020480. Its totient is φ = 910342220040.
The previous prime is 1411030441313. The next prime is 1411030441391. The reversal of 1411030441341 is 1431440301141.
1411030441341 is a `hidden beast` number, since 1 + 4 + 1 + 10 + 304 + 4 + 1 + 341 = 666.
It is not a de Polignac number, because 1411030441341 - 213 = 1411030433149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1411030441391) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2528728111 + ... + 2528728668.
Almost surely, 21411030441341 is an apocalyptic number.
It is an amenable number.
1411030441341 is a deficient number, since it is larger than the sum of its proper divisors (692871579139).
1411030441341 is a wasteful number, since it uses less digits than its factorization.
1411030441341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5057456816 (or 5057456813 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 1411030441341 its reverse (1431440301141), we get a palindrome (2842470742482).
The spelling of 1411030441341 in words is "one trillion, four hundred eleven billion, thirty million, four hundred forty-one thousand, three hundred forty-one".
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