1411033304131 has 8 divisors (see below), whose sum is σ = 1539317791728. Its totient is φ = 1282750272000.

The previous prime is 1411033304111. The next prime is 1411033304137. The reversal of 1411033304131 is 1314033301141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411033304131 is a prime.

It is a super-2 number, since 2×1411033304131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1411033304096 and 1411033304105.

It is not an unprimeable number, because it can be changed into a prime (1411033304137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3082471 + ... + 3510511.

It is an arithmetic number, because the mean of its divisors is an integer number (192414723966).

Almost surely, 2^{1411033304131} is an apocalyptic number.

1411033304131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1411033304131 is a deficient number, since it is larger than the sum of its proper divisors (128284487597).

1411033304131 is a wasteful number, since it uses less digits than its factorization.

1411033304131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 727733.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1411033304131 its reverse (1314033301141), we get a palindrome (2725066605272).

The spelling of 1411033304131 in words is "one trillion, four hundred eleven billion, thirty-three million, three hundred four thousand, one hundred thirty-one".