Base | Representation |
---|---|
bin | 11010010010000101… |
… | …01011111101100011 |
3 | 1100102101002200201201 |
4 | 31021002223331203 |
5 | 212344221434021 |
6 | 10252053342031 |
7 | 1006444636162 |
oct | 151102537543 |
9 | 40371080651 |
10 | 14110343011 |
11 | 5a90a14606 |
12 | 2899637917 |
13 | 143b4343bb |
14 | 97bddb3d9 |
15 | 578b7c591 |
hex | 3490abf63 |
14110343011 has 4 divisors (see below), whose sum is σ = 14376575952. Its totient is φ = 13844110072.
The previous prime is 14110343003. The next prime is 14110343021. The reversal of 14110343011 is 11034301141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11034301141 = 67369 ⋅163789.
It is not a de Polignac number, because 14110343011 - 23 = 14110343003 is a prime.
It is a super-2 number, since 2×141103430112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14110343011.
It is not an unprimeable number, because it can be changed into a prime (14110343021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133116391 + ... + 133116496.
It is an arithmetic number, because the mean of its divisors is an integer number (3594143988).
Almost surely, 214110343011 is an apocalyptic number.
14110343011 is a deficient number, since it is larger than the sum of its proper divisors (266232941).
14110343011 is an equidigital number, since it uses as much as digits as its factorization.
14110343011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 266232940.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 14110343011 its reverse (11034301141), we get a palindrome (25144644152).
The spelling of 14110343011 in words is "fourteen billion, one hundred ten million, three hundred forty-three thousand, eleven".
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