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1411041212213 = 5712471175503
BaseRepresentation
bin10100100010001000100…
…111000011011100110101
311222220010212222111020112
4110202020213003130311
5141104303022242323
63000120130112405
7203641626260063
oct24421047033465
94886125874215
101411041212213
114a4467a84466
121a9576a1b705
13a30a3230a39
144c41ab67033
1526a87640178
hex148889c3735

1411041212213 has 4 divisors (see below), whose sum is σ = 1413512388288. Its totient is φ = 1408570036140.

The previous prime is 1411041212179. The next prime is 1411041212249. The reversal of 1411041212213 is 3122121401141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1411041212213 - 238 = 1136163305269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411041202213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1235587181 + ... + 1235588322.

It is an arithmetic number, because the mean of its divisors is an integer number (353378097072).

Almost surely, 21411041212213 is an apocalyptic number.

It is an amenable number.

1411041212213 is a deficient number, since it is larger than the sum of its proper divisors (2471176075).

1411041212213 is an equidigital number, since it uses as much as digits as its factorization.

1411041212213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2471176074.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 1411041212213 its reverse (3122121401141), we get a palindrome (4533162613354).

The spelling of 1411041212213 in words is "one trillion, four hundred eleven billion, forty-one million, two hundred twelve thousand, two hundred thirteen".

Divisors: 1 571 2471175503 1411041212213