14110413133 has 4 divisors (see below), whose sum is σ = 14114632320. Its totient is φ = 14106193948.

The previous prime is 14110413113. The next prime is 14110413139. The reversal of 14110413133 is 33131401141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33131401141 = 107 ⋅309639263.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14110413133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14110413139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2104573 + ... + 2111266.

It is an arithmetic number, because the mean of its divisors is an integer number (3528658080).

Almost surely, 2^14110413133 is an apocalyptic number.

It is an amenable number.

14110413133 is a deficient number, since it is larger than the sum of its proper divisors (4219187).

14110413133 is an equidigital number, since it uses as much as digits as its factorization.

14110413133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4219186.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 14110413133 its reverse (33131401141), we get a palindrome (47241814274).

The spelling of 14110413133 in words is "fourteen billion, one hundred ten million, four hundred thirteen thousand, one hundred thirty-three".