Base | Representation |
---|---|
bin | 10100100010001000100… |
… | …111011110010010000001 |
3 | 11222220010220012001222220 |
4 | 110202020213132102001 |
5 | 141104303034301423 |
6 | 3000120132321253 |
7 | 203641630225353 |
oct | 24421047362201 |
9 | 4886126161886 |
10 | 1411041322113 |
11 | 4a4468049a95 |
12 | 1a9576a73229 |
13 | a30a326ba77 |
14 | 4c41ab950d3 |
15 | 26a876629e3 |
hex | 148889de481 |
1411041322113 has 8 divisors (see below), whose sum is σ = 1932236765568. Its totient is φ = 915270046704.
The previous prime is 1411041322111. The next prime is 1411041322183. The reversal of 1411041322113 is 3112231401141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1411041322113 - 21 = 1411041322111 is a prime.
It is a super-2 number, since 2×14110413221132 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1411041322111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6356041881 + ... + 6356042102.
It is an arithmetic number, because the mean of its divisors is an integer number (241529595696).
Almost surely, 21411041322113 is an apocalyptic number.
It is an amenable number.
1411041322113 is a deficient number, since it is larger than the sum of its proper divisors (521195443455).
1411041322113 is a wasteful number, since it uses less digits than its factorization.
1411041322113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12712084023.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 1411041322113 its reverse (3112231401141), we get a palindrome (4523272723254).
The spelling of 1411041322113 in words is "one trillion, four hundred eleven billion, forty-one million, three hundred twenty-two thousand, one hundred thirteen".
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