1411050113241 has 4 divisors (see below), whose sum is σ = 1881400150992. Its totient is φ = 940700075492.

The previous prime is 1411050113203. The next prime is 1411050113257. The reversal of 1411050113241 is 1423110501141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1411050113241 - 2⁹ = 1411050112729 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1411050113441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235175018871 + ... + 235175018876.

It is an arithmetic number, because the mean of its divisors is an integer number (470350037748).

Almost surely, 2^{1411050113241} is an apocalyptic number.

It is an amenable number.

1411050113241 is a deficient number, since it is larger than the sum of its proper divisors (470350037751).

1411050113241 is an equidigital number, since it uses as much as digits as its factorization.

1411050113241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 470350037750.

The product of its (nonzero) digits is 480, while the sum is 24.

Adding to 1411050113241 its reverse (1423110501141), we get a palindrome (2834160614382).

The spelling of 1411050113241 in words is "one trillion, four hundred eleven billion, fifty million, one hundred thirteen thousand, two hundred forty-one".