Base | Representation |
---|---|
bin | 100000000101010110100110… |
… | …010101000000101110001011 |
3 | 200111121112120112100102100211 |
4 | 200011112212111000232023 |
5 | 121443332224340220243 |
6 | 1220034523045141551 |
7 | 41502345066443110 |
oct | 4005264625005613 |
9 | 614545515312324 |
10 | 141105351101323 |
11 | 40a624970a6924 |
12 | 139ab1b46ba8b7 |
13 | 609723ccc7acb |
14 | 26bb76d32c907 |
15 | 114a719b48d9d |
hex | 8055a6540b8b |
141105351101323 has 4 divisors (see below), whose sum is σ = 161263258401520. Its totient is φ = 120947443801128.
The previous prime is 141105351101303. The next prime is 141105351101359. The reversal of 141105351101323 is 323101153501141.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 141105351101323 - 25 = 141105351101291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141105351101303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10078953650088 + ... + 10078953650101.
It is an arithmetic number, because the mean of its divisors is an integer number (40315814600380).
Almost surely, 2141105351101323 is an apocalyptic number.
141105351101323 is a deficient number, since it is larger than the sum of its proper divisors (20157907300197).
141105351101323 is an equidigital number, since it uses as much as digits as its factorization.
141105351101323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20157907300196.
The product of its (nonzero) digits is 5400, while the sum is 31.
The spelling of 141105351101323 in words is "one hundred forty-one trillion, one hundred five billion, three hundred fifty-one million, one hundred one thousand, three hundred twenty-three".
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