14111020333121 has 8 divisors (see below), whose sum is σ = 14113740780840. Its totient is φ = 14108300160768.

The previous prime is 14111020333099. The next prime is 14111020333141. The reversal of 14111020333121 is 12133302011141.

14111020333121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 8751035986225 + 5359984346896 = 2958215^2 + 2315164^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14111020333121 - 2⁶ = 14111020333057 is a prime.

It is a super-3 number, since 3×14111020333121³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14111020333141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 122522255 + ... + 122637371.

It is an arithmetic number, because the mean of its divisors is an integer number (1764217597605).

Almost surely, 2^{14111020333121} is an apocalyptic number.

It is an amenable number.

14111020333121 is a deficient number, since it is larger than the sum of its proper divisors (2720447719).

14111020333121 is a wasteful number, since it uses less digits than its factorization.

14111020333121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137683.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 14111020333121 its reverse (12133302011141), we get a palindrome (26244322344262).

The spelling of 14111020333121 in words is "fourteen trillion, one hundred eleven billion, twenty million, three hundred thirty-three thousand, one hundred twenty-one".