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14111020333122 = 2318713125679299
BaseRepresentation
bin1100110101010111101001…
…0110101011100001000010
31211222000000021021020001020
43031111322112223201002
53322143332201124442
650002302510050310
72654326144536126
oct315257226534102
954860007236036
1014111020333122
1145504a5117109
1216ba9881a9996
137b4881959c5b
1436ad96d73586
151970d78919ec
hexcd57a5ab842

14111020333122 has 16 divisors (see below), whose sum is σ = 28223549042400. Its totient is φ = 4703422048352.

The previous prime is 14111020333099. The next prime is 14111020333141. The reversal of 14111020333122 is 22133302011141.

14111020333122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 14111020333092 and 14111020333101.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62727372 + ... + 62951927.

It is an arithmetic number, because the mean of its divisors is an integer number (1763971815150).

Almost surely, 214111020333122 is an apocalyptic number.

14111020333122 is an abundant number, since it is smaller than the sum of its proper divisors (14112528709278).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14111020333122 is a wasteful number, since it uses less digits than its factorization.

14111020333122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125698017.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 14111020333122 its reverse (22133302011141), we get a palindrome (36244322344263).

The spelling of 14111020333122 in words is "fourteen trillion, one hundred eleven billion, twenty million, three hundred thirty-three thousand, one hundred twenty-two".

Divisors: 1 2 3 6 18713 37426 56139 112278 125679299 251358598 377037897 754075794 2351836722187 4703673444374 7055510166561 14111020333122